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Classical Field Theory

Lagrangian densities, Klein–Gordon equation, and the bridge to QFT.

Promote $L(q,\dot q) \to \mathcal L(\phi, \partial_\mu \phi)$ — a Lagrangian density depending on a field $\phi(x)$ and its spacetime derivatives. The action is $S = \int d^4x\, \mathcal L$. Euler–Lagrange for fields:

$$\partial_\mu \frac{\partial \mathcal L}{\partial (\partial_\mu \phi)} - \frac{\partial \mathcal L}{\partial \phi} = 0.$$

The simplest relativistic scalar:

$$\mathcal L = \tfrac{1}{2}(\partial_\mu \phi)(\partial^\mu \phi) - \tfrac{1}{2}m^2 \phi^2$$

gives the Klein–Gordon equation $(\Box + m^2)\phi = 0$. Plane-wave solutions $\phi = e^{-ik\cdot x}$ have dispersion $\omega^2 = \mathbf k^2 + m^2$ — relativistic energy of a particle of mass $m$.

Interactive: scalar field oscillation

Click to drop a Gaussian perturbation; watch dispersive Klein–Gordon waves propagate.

Quiz

1. The Klein–Gordon equation is:
2. Plane-wave KG solutions obey:
3. Euler–Lagrange equations for a field follow from extremizing:
4. Noether's theorem for a continuous internal symmetry yields:
5. If $\mathcal L$ depends only on $\partial_\mu \phi$ (not on $\phi$ itself), then: