Postgraduate Science

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Renormalization & Running Couplings

Why couplings depend on the scale you probe — Wilson's view of QFT.

Loop integrals in QFT diverge at high momentum. Regulate (dimensional regularization, momentum cutoff Λ) and renormalize by absorbing the divergences into a finite number of bare parameters. What remains finite are physical observables, expressed in terms of measured parameters at a reference scale.

The coupling depends on the energy scale $\mu$:

$$\mu \frac{dg}{d\mu} = \beta(g).$$

For QED: $\beta_{\rm QED} > 0$, so $\alpha$ grows with energy ($1/137 \to 1/127$ at the $Z$ pole). For QCD: $\beta_{\rm QCD} < 0$, so $\alpha_s$ shrinks at high energy — asymptotic freedom (Gross, Politzer, Wilczek, 2004 Nobel).

A renormalizable theory needs only finitely many counterterms; non-renormalizable theories (e.g., quantum gravity in 4D) require infinitely many — they are effective theories valid only below some scale.

Interactive: running couplings vs energy

Quiz

1. Asymptotic freedom means the strong coupling $\alpha_s$:
2. The QED coupling at the $Z$-pole ($\mu \sim 91$ GeV) is roughly:
3. A non-renormalizable theory:
4. In Wilson's coarse-graining picture, irrelevant couplings:
5. The anomalous dimension of an operator is: